First, we need to determine the decay process. In a β+ decay, a proton is converted into a neutron, a positron, and a neutrino. So, the decay process for ${ }_{11}^{22} \mathrm{Na}$ can be written as:
${ }_{11}^{22} \mathrm{Na} \rightarrow { }_{10}^{22}
Show more…