Therefore, we can write the equation as follows:
\[\frac{1}{2} C V_{oc}^2 = \frac{1}{2} L I_{o}^2\]
where \(C\) is the capacitance, \(V_{oc}\) is the peak capacitor voltage, \(L\) is the inductance, and \(I_{o}\) is the peak inductor current.
Show more…