00:01
Hi, here in this given problem, in the given lrc series circuit, self -inductance of the coil that is 0 .450 henry, capacitance of the capacitor 2 .50 multiplied by 10 raised to the power minus 5 farad.
00:26
In the first part of the problem when resistance of the circuit is 0, we have to find angular frequency of the circuit and that will be given by 1 upon under root lc.
00:42
So plugging in the known values for self -inductance, this is 0 .450 multiplied by capacitance 2 .50 multiplied by 10 to the power minus 5 and this angular frequency is calculated to be equal to 298 .14 radian per second, answer for the first part of this given problem here.
01:08
Now in the second part of the problem, if the resistance is non -zero, then a loss of energy will take place in this circuit and now the angular frequency that is given as 5 percent less than the original one means it is 95 percent of the original one means we can say this is 95 by 100 of 298 .14.
01:36
So it comes out to be equal to 283 .24 radian per second.
01:49
Now angular frequency in that case is given as square root of 1 by lc minus r square by 4l square.
02:00
First of all, we will be using the original formula for omega and that was 1 upon under root lc...