00:01
We have simple harmonic motion.
00:01
The object's position as a function of time would be equaling the amplitude multiplied by cosine of and the angular frequency multiplied by time plus the phase constant finite.
00:12
Now we can let the initial position be zero at, of course, t equals zero seconds.
00:21
So zero equaling a cosine of phi knot.
00:26
Phi not is then equaling plus or minus pi over two radians.
00:35
Now, the object is traveling to the right in the lower half of the circular motion diagram.
00:43
So we know that we can say moving to the right, we can say lower half of circle or circular motion diagram.
01:00
And so we find that then the phase constant is definitely equalling negative pi over two ratings.
01:09
So given that, we can say that then the exposition as a function of time would be equaling a cosine of omega -t minus pi over two.
01:24
This would then a rather, this would become exposition as a function of time equaling a, a sign of omega t.
01:38
And so this would be equaling to 0 .10 meters multiplied by sine of pi multiplied by t over 2...