Question
An object in simple harmonic motion has amplitude 4.0 $\mathrm{cm}$ and frequency $4.0 \mathrm{Hz},$ and at $t=0 \mathrm{s}$ it passes through the equilibrium point moving to the right. Write the function $x(t)$ that describes the object's position.
Step 1
Step 1: The position of an object in simple harmonic motion is given by the function $x(t) = A\cos(\omega t + \phi)$, where $A$ is the amplitude, $\omega$ is the angular frequency, $t$ is the time, and $\phi$ is the phase constant. Show more…
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