Question
An object in simple harmonic motion has an amplitude of $8.0 \mathrm{cm},$ a frequency of $0.25 \mathrm{Hz},$ and a phase constant of $-\pi / 2$ rad. Draw a position graph showing two cycles of the motion.
Step 1
The general form of this equation is $x(t) = A \cos(\omega t + \phi)$, where $A$ is the amplitude, $\omega$ is the angular frequency, $t$ is the time, and $\phi$ is the phase constant. Show more…
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