00:01
Okay, so here's a rough sketch of this situation.
00:04
You've got an object here, and the image of that object, whenever it's reflected in this mirror, is twice the size and inverted.
00:15
So we are seeing a real and inverted.
00:23
So this means that the height of the image is equal to negative 2h for the object.
00:33
We can use that information to start to figure out some more information about this image.
00:41
So we're going to use the magnification relation, which is negative q over p.
00:48
And we know that that is equal to negative 2 .0.
00:54
So to solve for q, we rearrange this so that we get 2 .0 times p.
01:03
And that is what we'll use for the position of the image.
01:08
So next we can use information about the focal length or information about the radius of curvature because the focal length is half that of the radius of curvature, which is 12 .5 centimeters.
01:26
Now we can use the focal length equation to solve for the position of this image or the position of the object, i'm sorry...