00:01
Okay, so here's a ray diagram of this scenario.
00:05
We've got an object positioned in front of a convex mirror and a virtual and upright image positioned here.
00:15
And we want to figure out where this object is positioned based on the fact that the magnif, or i'm sorry, based on the fact that the image is half the height of the object.
00:28
So we can start with the magnification relation that is equal to negative q over p.
00:36
And that's going to be equal to the height of the image over the height of the object.
00:43
The height of the image over the height of the object is equal to one half.
00:49
So that is good information.
00:50
And then we can start to simplify in order to solve for q.
00:55
Q would be negative 1 1ā2 times p, and that will be our value for q later on, 1 half p.
01:13
Next we need is the focal length equation.
01:18
Oh, i'm sorry, we're actually, we actually need to consider the focal length based on the information they tell us about the curvature radius...