An object is placed to the left of a lens, and a real image...

An object is placed to the left of a lens, and a real image is formed to the right of the lens. The image is inverted relative to the object and is one-half the size of the object. The distance between the object and the image is $90.0 \mathrm{~cm} . \quad$ (a) How far from the lens is the object? (b) What is the focal length of the lens?

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Real Image Formation

A real image is formed when light rays converge at a point after passing through a lens, allowing the image to be projected onto a screen. Real images are typically inverted relative to the object. This concept is crucial in optics as it distinguishes between cases where an image can be captured on a surface versus scenarios where the image remains virtual and cannot be directly projected.

Lens Equation

The lens equation (1/f = 1/do + 1/di) relates the focal length of a lens to the distances of the object (do) and the image (di) from the lens. This fundamental formula is key to calculating any one of these parameters when the other two are known, and it applies to both converging and diverging lenses under the appropriate sign conventions.

Magnification

Magnification is defined as the ratio of the image height to the object height and is mathematically expressed as m = -di/do. The negative sign indicates that if the image is inverted relative to the object, the magnification will be negative. Understanding magnification helps in determining how the size of the image compares to the size of the object.

Transcript

Please give Ace some feedback