Question
An object is thrown upward at time $t=0 .$ After $t$ seconds, its height is $y=-4.9 t^{2}+7 t+1.5$ meters above the ground.(a) From what height was the object thrown?(b) What is the initial velocity of the object?(c) What is the acceleration due to gravity?
Step 1
Substituting $t=0$ into the equation for $y$, we get \[y = -4.9(0)^2 + 7(0) + 1.5 = 1.5\] So, the object was thrown from a height of $\boxed{1.5}$ meters. Show more…
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