an-object-of-mass-2-mathrmkg-has-a-linear-momentum-of-magnitude-6-mathrmkg-mathrmm-mathrms-what-is-t

Question

An object of mass 2 $\mathrm{kg}$ has a linear momentum of magnitude 6 $\mathrm{kg}$ .$\mathrm{m} / \mathrm{s} .$ What is this object's kinetic energy?
(A) 3 $\mathrm{J}$
(B) 6 $\mathrm{J}$
(C) 9 $\mathrm{J}$
(D) 12 $\mathrm{J}$

Khoobchandra Agrawal · Accepted Answer

Hi, everybody here it is given of particle of mass. Two kg is moving with linear momentum off six kg meter per second. We have to find it&#x27;s kind of technology has been no kinetic energies to find us. Please square by To him, Mom p is linear momentum who Mars is. So it should be nine June hence answer sees. Correct. That&#x27;s all. Thanks for watching it.

Ze-Han Lee · Answer

So in this problem, we know that the mass off the object and me quote too kilograms. And the moment, um is a six kilograms meters per second. So the kind that energy we&#x27;ll have expression p split over to at all. Right, So peace quit is 36 2 and four. So this gives us nine jokes.

Salamat Ali · Answer

This is an inelastic collision. So masses stick to each other after the collision so we can write to the initial momentum Eyes m one and he shall be one initial plus mass to, uh, V two, um, initial that isn&#x27;t called thio. Two masses sticking with each other. So then one plus into they are going with the final velocity together, which is where we if then a substantive value we can find it. We f here will be a three times three. This is initial mass and the mass one end everyone plus ah two times minus six. Derided by some off masses which is a five kg then divided. These numbers gives us a minus their reports six meter per second for a second. So option B is the right answer.

Amy Jiang · Answer

Okay. So we would solve our following expression given RM and be so that&#x27;s 1/2 times a 60 a time six squared. So we have 60.5 times 60 times 60 depart to, and that&#x27;s equal to 10 80.

Ze-Han Lee · Answer

So in this problem we have Ah, we have force acting on the object and the velocity off the off the object that range. It starts from three meters per second to six meters per second. So we want to know the work down in this process. So according to the energy of a vision, law would say that the work in this process equal the final kinetic energy minus the initial kind. Kind of static energy, right? We already know the mass and the velocity are giving the problem so I can see that this equal 54 Jos, hurry.

Ren Jie Tuieng · Answer

No. The first ball discussion looks at the kinetic energy. Also object And could I take energy? Justify s half empty square VSD magnitudes off. Ah, lost it. So we just need to find ISS Led many to off. Thank you to square off. Uh, velocity off the object in this case is just taking the i component square last e j component square. There&#x27;s just six square plus one square. This case l mess is ready given to be tree kitschy. So substituting everything in we should get a value off 55.5 juice Moving on to read expert multi question are involved looking. It&#x27;s ah, the total net done on the object When? If you don&#x27;t see changes, right. So whenever you see changes what infection justice? D kinetic energy. So we can finally network done by simply Okay, what is t change? Anti kinetic energy. This case we take half and times the final bill C squared. Why does a lady huff often the initial velocity squared really know that? Oh, initial velocity you can take, uh, this sixth grade class one square right to B C initial velocity squared and our final velocity squared iss actually eat square pass foreswear, right? So I just have to substitute any mess which is tree K g. You know, I very this expression to get 34.5 juice, So desist e that well done.

Problem

A ball of mass 0.5 $\mathrm{kg}$ , initially at r…

Problem 1 Easy Difficulty

An object of mass 2 $\mathrm{kg}$ has a linear momentum of magnitude 6 $\mathrm{kg}$ .$\mathrm{m} / \mathrm{s} .$ What is this object's kinetic energy?
(A) 3 $\mathrm{J}$
(B) 6 $\mathrm{J}$
(C) 9 $\mathrm{J}$
(D) 12 $\mathrm{J}$

Answer

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