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An object of mass $m$ is traveling at constant speed $v$ in a circular path of radius $r .$ How much work is done by the centripetal force during one-half of a revolution?(A) $\pi m v^{2}$(B) 0(C) $\pi m v^{2} r$(D) 2$\pi m v^{2} r$

Physics 101 Mechanics

Chapter 7

Uniform Circular Motion, Newton’s Law of Gravitation, and Rotational Motion

Gravitation

Dynamics of Rotational Motion

Cornell University

University of Washington

Simon Fraser University

University of Winnipeg

Lectures

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in this problem, we want to find work done by a centripetal force doing one half revolution as we can. Wild work done by centrifugal force equals toe judging kinetic energy off object s object is winning with constant See Pete so kinetic energy off object we lost to be constant These users church in kinetic energy of object equal toe zero. So we can say that work done by centripetal force will be called toe zero. We can also explain this as work done by a centripetal force Physical toe centrifugal force dot displacement is in case off circular motion. Centripetal force is always really in what? And each and at each point, we have the angle between with displacement director and force Equal toe 90 degree so we can write well done by. So do better force equal toe So tubular force in tow, Displacement in tow. Sign off 90 degree. This gives us work done by centripetal force Equal toe Jiro. So at each might we have well done by a centripetal force equal toe zero So this users work done by contributor force in one house revolution is also equal toe zero

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