Question
An object's distance from a converging lens is 5.00 times the focal length. (a) Determine the location of the image. Express the answer as a fraction of the focal length. (b) Find the magnification of the image and indicate whether it is (c) upright or inverted and (d) real or virtual.
Step 1
We can denote the focal length as $f$ and the object distance as $p$. According to the sign convention, the object distance is always taken as negative. Therefore, $p = -5f$. Show more…
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(a) For a converging lens with a focal length of $3.50 \mathrm{cm}$ find the object distance that will result in an inverted image with an image distance of $5.00 \mathrm{cm} .$ Use a ray diagram to verify your calculations. (b) Is the image real or virtual? (c) What is the magnification?
A real object’s distance from a converging lens is five times the focal length. (a) Determine the location of the image q in terms of the focal length f. (b) Find the magnification of the image. (c) Is the image real or virtual? Is it upright or inverted? Is the image on the same side of the lens as the object or on the opposite side?
A converging lens has a focal length of 10.0 cm. Locate the images for object distances of (a) 20.0 cm, (b) 10.0 cm, and (c) 5.00 cm, if they exist. For each case, state whether the image is real or virtual, upright or inverted, and find the magnification.
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