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Hi there.
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This is problem number 41.
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It is an open -ended monometer problem.
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A monometer is a glass tube in a u shape, and it typically has some mercury in it.
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So we might start off with maybe that much mercury in this tube.
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All right, for this monometer in this problem, the end that is open to the atmosphere is registering an atmospheric pressure of 748 tor.
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The other end is attached to the container of our gas sample.
00:49
And we do not know the pressure of our gas.
00:52
However, what we do know is when these two are interacting, in other words, the atmospheric pressure and the gas pressure, we find that on the side of the air, the mercury is 6 .5 or 65 millimeters higher.
01:19
So maybe we have something that looks like this, where the difference between the left side and the right side is 65 millimeters.
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And this all represents the mercury.
01:48
Okay, so if we think about what's going on here, we're trying to find the pressure of the gas.
01:54
If we think about what's going on here, if we think about it in terms of the analogy of a teeter -totter.
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If you have a little teeter -totter and it is level, but somebody comes along and takes away, pushes down harder on the right side than another person does on the left side, what's heater -totter is going to do.
02:15
It's going to go down on the right side and up on the left side.
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So that's what we're seeing here.
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The right side is lower than the left side, which is open to the atmosphere.
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That means that the pressure of the gas on the right side must be greater than the pressure of the atmosphere...