00:01
Hey guys, in this problem, we are told that a person has a contact lens prescription of negative point for diopeters.
00:10
And we're trying to find the far point.
00:11
So first step is first.
00:13
We need to find what the power of the person's eye is with his lenses.
00:18
So in order to do this, we're going to take the normal distance division.
00:25
Basically, in order to find the contact lens prescription, what you do is you take the 50 diopeters and you subtract it from a value x.
00:33
Now, in this case, our value x is unknown, but in reality, our x is representing the total power of the person's eye, including the person's i plus the person's lens power.
00:46
And that's what we need to solve for it.
00:47
So 50 minus x is going to be equivalent to negative 4 .00.
00:52
This is the formula for our total power, in a sense, because we have our, i'll replace this x with the better, variable in a sense.
01:04
So let's take out this x and let's call it pt...