00:03
Okay, in this problem, what the tension reads is the difference between the gravitational force and the buoyant force.
00:13
Basically, the bigger the buoyant forces, the lighter the sample of ore is going to appear.
00:18
So we're given that the force of tension is 11 .2, and the force of gravity is 17 .5.
00:29
So we know as well that the point force is given by the density of water times the gravitational acceleration times the volume of the object.
00:44
So if we want to know the volume of the object, it's simply, actually let's include all the algebra here.
00:56
So we have row, water, times g, times v, object is equal to 17 .5 minus 11 .2.
01:16
And so altogether, the object, which is our ore sample, is equal to 17 .5 minus 11 .2, divided by 9 .8, is the gravitational acceleration and divided as well by the density of water, which is 10 to 3 kilograms per meter cubed...