00:02
So we know delta t is equal to i b k f.
00:09
So we have to calculate molar mass.
00:20
Okay.
00:21
And first thing first, we know delta t is equal to t solvent minus t solution.
00:31
So solvent is 178 .4, which is camphor and 1 .4.
00:37
48 .4 this is given to us right so 20 .0 now b is equal to delta t over i k f i is equal to 1 this is 20 degrees celsius 1 into 37 .7 degrees celsius kg per mole so this gives us an answer of 0 .53 3 mole per kg.
01:15
B solute is equal to n solute over m solvent or camphor okay so mass of camphor is equal to 1 .10 grams which is equal to 0 .001 kgis right so n solute is equal to b solute into m camphor.
01:55
So this is 0 .53 mole per kg into 0 .001 kg, right? so this is 5 .83 10 to the power minus 4 moles.
02:13
Now number of moles is equal to mass over molar mass.
02:26
Therefore molar mass of solute is equal to given mass which is 0 .09 grams divided by 5 .83 10 to the power minus 4.
02:42
So this is 154 .4 .4 grams per mole.
02:47
This is a molar mass right? so we are given 93 .46 % carbon and 6 .54 .4.
02:59
4 % hydrogen, right? so we'll use this formula.
03:07
Mc over mx.
03:10
Okay, x is the solute...