Question
An organic compound is found to have the formula $\mathrm{C}_5 \mathrm{H}_{10} \mathrm{ONCl}$. The percentage of nitrogen present in it is(a) $23.36 \%$(b) $10.3 \%$(c) $41.05 \%$(d) $5.06 \%$
Step 1
This indicates that the compound contains 5 carbon (C) atoms, 10 hydrogen (H) atoms, 1 oxygen (O) atom, 1 nitrogen (N) atom, and 1 chlorine (Cl) atom. Show more…
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An organic compound is found to have the formula $\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{ONCl}$. The percentage of nitrogen present in it is (a) $23.36 \%$ (b) $10.3 \%$ (c) $41.05 \%$ (d) $5.06 \%$
In the estimation by Duma's method, $0.59 \mathrm{~g}$. of an organic compound gave $112 \mathrm{~mL}$ nitrogen at NTP. The percentage of nitrogen in the compound is about (a) $23.7$ (b) $16.8$ (c) $33.07$ (d) $27.5$
In an organic compound of molar mass is $108 \mathrm{~g} \mathrm{~mol}^{-1}$. $\mathrm{C}, \mathrm{H}$ and $\mathrm{N}$ atoms are present in $9: 1: 35$ by weight in it. Molecular formula can be (a) $\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{~N}_{2}$ (b) $\mathrm{C}_{7} \mathrm{H}_{10} \mathrm{~N}$ (c) $\mathrm{C}_{5} \mathrm{H}_{6} \mathrm{~N}_{3}$ (d) $\mathrm{C}_{4} \mathrm{H}_{18} \mathrm{~N}_{3}$
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