00:01
And today we'll be solving a problem which states that rl circuit has emf of et, which is equal to 10 times sine of 4t volts.
00:13
If r is equal to 2 oms and l is equal to 2 3rd henrys and assuming just there is no current flowing initially, determine the current for t is greater than 0.
00:25
So the first thing we'll do is we'll get to write down our differential equation for the rl circuit.
00:29
So that'll be i prime plus r over l times i just all equal to et over l.
00:44
Know that r is equal to two.
00:49
L is equal to two thirds.
00:53
E t is equal to 10, sine 4t.
01:03
And we know that there's no current flowing initially.
01:05
So i zero is equal to zero.
01:09
So what we do next is that we're going to plug in everything into our differential equation.
01:18
So if i prime plus two over two thirds times i, is that equal to 10 sine 4 t? that's all over two thirds.
01:37
So after simplifying everything, what we get as i prime plus three i, which is equal to 15, sine 4 t.
01:52
So what we get into the next is that we're going to write e to the integral over coefficient x to i, which is 3.
02:01
You let that respect to d to t.
02:06
So when solving this, what you get is e to the 3t...