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An rms voltage of 22.2 V with a frequencyof 1.00 kHz is applied to a 0.290-mH inductor. (a) What is the rmscurrent in this circuit? (b) By what factor does the current changeif the frequency of the voltage is doubled? (c) Calculate the current for a frequency of 2.00 kHz.
a) 12.2 $\mathrm{A}$b) 0.500c) 6.09 $\mathrm{A}$
Physics 102 Electricity and Magnetism
Chapter 24
Alternating-Current Circuits
Current, Resistance, and Electromotive Force
Direct-Current Circuits
Electromagnetic Induction
Alternating Current
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in the first item, we have to cock a little r m s current that flows from the circuit. And to do that, we begin by using some sort off owns well, which is given by V or a mass is he goes to Why a rematch? Times impedance. Remember that thing peons off on in doctor is he goes to to pi times the frequency times they looked at us. Then the army's current through that circuit is equals two the voltage divided by two pipe times the frequency times the doctor's looking The value is giving in the problem. We have 22.2 divided by two pi times one times 10 to the third It is one kilo hurt times 0.2 29 Time stand to the minor street because it is Emilie, Harry And then all these is approximately 12 points too empty years in the second item we have to calculate by what factor does they couldn't change is if we double the frequency. So know that the relation between the current and the frequency is the following You're a mess. Is the coast v ery mass divided by two piped into the frequency times the victims. No, if we do as going to two times f, then we will have a new current I prime with Zikos too. V r E mass divided by two pi times two times f times inductive and finally dividing these new current by the previous one we get that is he goes to the voltage divided by two pi times two time the frequency times conductors divided by involved in divided by two pi times the frequency times they looked at us simply find everything we can You're left with a factor off one over to which is he goes to 0.5 in the last item we have a frequency off too kilohertz So we have multiplying the frequency by a factor of two, we have doubled the frequency. Then we can use our result from the first item and the result from the second item To get that in this case, the current we'll be 0.5 times the current in the previous case, which is 12 point to these is equal to 6.1 amperes
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The number 2 is also the smallest & first prime number (since every other even number is divisible by two).
If you write pi (to the first two decimal places of 3.14) backwards, in big, block letters it actually reads "PIE".
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