00:01
Let's start with our reaction here.
00:04
We're told that we have mx2, 2 mx2 solid.
00:09
That's going to produce 2mx solid and x2 gas.
00:17
The identities of m and x are unknown.
00:22
We have 1 .12 grams of mx2, which is going to produce 0 .72 grams, 0 .720 grams of mx2.
00:31
And by difference here we can find that we have 0 .40 grams of the x2.
00:36
So for a, we need to, we're asked to find the atomic mass and the identity for halogen x.
00:44
Let's calculate the molar mass for x2, which would be, we were told that 56 .0 milliliters of x2.
00:58
Now we know that this has a mass of 0 .1 .1.
01:03
0 .40 grams.
01:04
We have this from our calculation up above by difference.
01:07
So we have 0 .40 grams over, now i'll convert 56 milliliters into liters, 0 .056 liters.
01:16
And to get molar mass here, 22 .4 liters is equivalent to one mole.
01:21
And this works at 160 grams per mole is the molar mass for element, for x2.
01:26
But we want the molar mass for just element x, which would be half of that, which would be 80 grams per mole...