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Problem 19 Easy Difficulty

An unstable particle at rest breaks up into two fragments of unequal mass. The mass of the lighter fragment is equal to 2.50 $\times 10^{-28} \mathrm{kg}$ and that of the heavier fragment is $1.67 \times 10^{-27} \mathrm{kg}$ . If the lighter fragment has a speed of 0.893 $c$ after the breakup, what is the speed of the heavier fragment?

Answer

0.285$c$

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Video Transcript

comma two times and two times We to is equal to gamma one times in one times we want. Let's plug in the values 1.67 multiplied by tend to the bomber, finest. 27 times we do you find it by ah, square root off one minus. We square divided by C square is equal to 2.50 Multiplied by 10 to the power minus 28 times zero find 893 times the speed of light divided by square root off one minus, uh, zero point 893 holes. Where and no solving for we, uh, We have B is equal to 0.2 eat five times the speed off.

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