00:01
In this problem, we are given an urn with red balls and blue balls.
00:05
Part a, what is the probability that at least one of the balls is red? so i've drawn a tree diagram already.
00:11
At least one red means we want at least one of these three branches.
00:17
So i've already written that in the notation form in part a, but recognize that this is the same thing as one minus the probability of b1 and b2.
00:26
That way i only have to calculate one branch instead of three.
00:30
This will be one minus two over eight times two over eight.
00:38
And that's going to give me 15 over 16 after i reduce it.
00:43
In part b, this is conditional.
00:46
So this is the probability of the second ball being red and at least one red over at least one red.
01:01
So on the top, look at the tree diagram and say, which branches have a second ball being red and at least one red.
01:12
Well, those are the two branches available that have r2.
01:16
So those are the branches that we want for the numerator.
01:20
That will be 6 over 8 times 6 over 8 plus 6 over 8 times 2 over 8...