Question
Angular mon constant due to central constant torque(a) corstant force constant force(b) constant(c) corbrorque (d) zero toryut $7 \hat{j}+3 \hat{j}-5 \hat{k}$ acts on a par
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The angular momentum of this particle is constant. We need to find out the reason for this. Show more…
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The torque of force $\vec{F}=(2 \hat{i}-3 \hat{j}+4 \hat{k})$ newton acting at the point $\vec{r}=(3 \hat{i}+2 \hat{j}+3 \hat{k})$ metre about origin is (in $\mathrm{N}-\mathrm{m}$ ) (A) $6 \hat{i}-6 \hat{j}+12 \hat{k}$ (B) $17 \hat{i}-6 \hat{j}-13 \hat{k}$ (C) $-6 \hat{i}+6 \hat{j}-12 \hat{k}$ (D) $-17 \hat{i}+6 \hat{j}+13 \hat{k}$
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