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Animal motion. Cheetahs, the fastest of the great cats, can reach 45 mph in 2.0 starting from rest. Assuming that they have constant acceleration throughout that time, find (a) their acceleration (in $\mathrm{ft} / \mathrm{s}^{2}$ and $\mathrm{m} / \mathrm{s}^{2}$ and (b) the distance (in $\mathrm{m}$ and ft) they travel during that time.

a) $a=\frac{20.1}{2} \approx 10 \mathrm{m} / \mathrm{s}^{2}$b) $d \approx 20 m$

02:53

Averell H.

Physics 101 Mechanics

Chapter 2

Motion along a Straight Line

Physics Basics

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Rutgers, The State University of New Jersey

Hope College

University of Winnipeg

McMaster University

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in this problem on the topic of motion in a straight line, we are told that cheetahs can reach a speed of 45 miles an hour in two seconds. Starting from rest, we want to find the acceleration of Akita in feet per square second, as well as meter per square second and the distance they can travel in the time in meters and feet. Now we can apply the mathematic equation. V X is equal to we not X plus a X times T. So the acceleration of the cheetah X is equal to its final speed, V x minus minus its initial speed. We not X divided by the time T. And so this is equal to Its speed of 20.1 meters the second, Which is 45 mph- Initial speed zero any time of two seconds. This gives us the acceleration of the cheetah to be 10 meters per square second and this is good 10 m/km2, Multiplied by three 281 ft over a meter. And so when you convert this, this becomes 33 feet per square second. So we have the acceleration of the cheetah in meters per square second and feet per square second. Okay, Next. For part B, we want to find the distance that he'd taken cover in this time in meters and feet. So you can use the charismatic equation of motion. X is equal to ex not plus Vinod, X times T plus a half A X T squared. And so this is a half times The acceleration in s. units 10 m/km2 Times a time of two seconds squared, since the initial velocity of the Jetta zero. And so the distance that they cover in this time is 20 m, which is a half times the acceleration, 33 ft per square second, using The nonstandard units times two seconds squared. And so this distance in feet is 66 ft

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