00:01
Of mass l and i'm going to start writing my diagram here and then i'll come back to it as we add more.
00:05
So i have a block, excuse me, of mass m and it is suspended by a row of length l and mass m from a ceiling.
00:19
Okay, and it's got a constant upward force, upward force pulling down.
00:27
And of course, this will be the mass of the system times g.
00:36
Down.
00:38
So this is the information we're given here.
00:40
And then over here i'm going to write, so in the vertical direction, we're, our sum of our forces in our y direction will be equal our force minus the mass of the system times g.
00:55
And that will equal the mass of the system.
01:03
Oops.
01:05
Oops, wrong one here.
01:12
A .y.
01:13
Okay.
01:14
So the mass of the system will equal m plus m and my force minus m plus m times g will equal m plus m plus a y so for a y we will have force minus m plus m g over m plus okay okay so we're going to assume that the rope is uniform it's uniformly distributed.
02:04
So its length density of the rope will be m divided by l.
02:19
So for the mass of any length of rope will equal l times this.
02:28
Mass of length.
02:34
Oops, that made a big mess there.
02:37
Mass of any length.
02:43
Okay.
02:45
So now we can say that mx, equals mx over l.
02:52
And now we're going to draw the force diagram of the segment of rope.
02:58
And let's do this.
03:03
So x equals l.
03:07
And then let's just go like this, any segment here.
03:12
So this is x.
03:16
This will be l minus x from here to here.
03:21
This is l...