00:01
Okay, so we want to react but to e -en, or two butene with the following reagents.
00:06
So the e -en is an al -keen.
00:08
The number indicates where the alkenes located, butane's four carbons, so on carbon 2.
00:17
And the first reagent is going to be hydrogen gas, h -2.
00:25
And this is just a simple reaction.
00:28
It's a simple reduction reaction.
00:30
We're going to reduce the al -keen to an al -cane, and hydrogen is going to add to each carbon of the al -keen.
00:45
Next one is c -lto with the same reagent.
00:56
And this is going to add to each carbon of the achine, but it's going to add in anti -addition, meaning that one group is going to be the front and one's in the back.
01:06
And this is just based upon the mechanism of the reaction.
01:11
So in the mechanism, we have this intermediate, if we had both groups in the front, or if we draw like this instead.
01:41
This is the intermediate, and the other chlorine is going to attack from the back.
01:46
To open the ring and it would give us this product.
01:58
So next reagent is br2.
02:01
And this is similar to cl too.
02:02
We're just going to add the bromine antideition.
02:08
So putting one here, another in the back.
02:14
Next one is hcl.
02:25
And this is known as an electrophilic addition reaction.
02:28
This is the electrophile hcl.
02:31
The nucleophile is the alkene.
02:34
And if we have an acid, it's going to be a proton donor.
02:38
The nuclear file will be a peritonexion.
02:41
This is also known as an electron donor, electron acceptor.
02:47
I think peritone is really the simplest way of looking at it.
02:51
It's going to grab proton from here.
02:53
We have a highly polarized balance of chlorine.
02:55
We'll get both electrons...