Answer the following questions in terms of the machine...

Name: Problem 2, Chapter 2: Computer Science - An Overview
Uploaded: 2021-09-29T15:39:47-08:00
Duration: 5 min 33 s
Channel: Shelby Mohamed
Description: Answer the following questions in terms of the machine language described in Appendix C. a. Write the instruction 2304 (hexadecimal) as a string of 16 bits. b. Write the op-code of the instruction B2A5 (hexadecimal) as a string of 4 bits. c. Write the operand field of the instruction B2A5 (hexadecimal) as a string of 12 bits.

Answer the following questions in terms of the machine language described in Appendix C. a. Write the instruction 2304 (hexadecimal) as a string of 16 bits. b. Write the op-code of the instruction B2A5 (hexadecimal) as a string of 4 bits. c. Write the operand field of the instruction B2A5 (hexadecimal) as a string of 12 bits.

Answer the following questions in terms of the machine language described in Appendix C.
a. Write the instruction 2304 (hexadecimal) as a string of 16 bits.
b. Write the op-code of the instruction B2A5 (hexadecimal) as a string of 4 bits.
c. Write the operand field of the instruction B2A5 (hexadecimal) as a string of 12 bits.

Key Concepts

Opcode Extraction

In the context of a machine language instruction, the opcode extraction involves isolating the portion of the instruction that indicates what operation the computer should perform. When an instruction is represented in a fixed format, such as a 16-bit word with a designated 4-bit opcode, one must extract these bits to determine the command as interpreted by the processor.

Operand Field Extraction

This concept concerns obtaining the relevant bits that represent the operand part of an instruction from its complete binary representation. For a 16-bit instruction where the operand might consist of 12 bits, the process involves ignoring the opcode bits and isolating the remaining bits that provide additional information required to execute the instruction.

Hexadecimal to Binary Conversion

This concept involves converting numbers between numeral systems, particularly from hexadecimal to binary. Since each hexadecimal digit represents exactly four binary bits, converting a hexadecimal instruction into a 16-bit binary string is done by replacing each hex digit with its corresponding four-bit binary sequence.

Machine Language Instruction Format

This key concept refers to the structured layout of machine instructions in a computer system. Typically, in a 16-bit instruction format, the bits are divided into fields such as an opcode and operand. The opcode field specifies the operation to be executed, while the operand field denotes associated data, an address, or other parameters needed for the operation.

Transcript

00:01 Hello, so in this problem we're going to answer three questions related to including some machine language codes.

00:13 So in the first question here we are asked to write the instruction 2304 as a string of 16 bit.

00:26 So this instruction here is written in hexadecimal notation, hexadecimal.

00:36 And we know that each digit in hexadecimal representation can be represented as four binary digits.

00:45 So for example, we will start applying one by one from the left to the right.

00:51 So the digit 2 in hexadecimal corresponds to 0 -0 -1 -0 in binary.

01:03 This refers to the hexadecimal 2.

01:09 Then the second one is 3, which is again 0 -0 -1.

01:17 That's 3 written in binary.

01:20 And then zero, that's simply all four digits being zero.

01:26 And finally, four, it's zero, one in the third bit here.

01:34 Zero, zero.

01:35 Being in the third bit, this is two to the power of two, which is definitely four.

01:40 So that's two, three, zero, four represented in binary notation.

01:45 Now let's move to b.

01:47 In b, we need to write the up code of the instruction b to a5 in hexadecimal and to write it as a string of 4 bits in binary notation, of course.

02:03 So the first thing here is to determine exactly which part of this instruction is the upcode.

02:10 So as we know, the first hexadecimal digit is what we call the upcode.

02:16 So here the upcode is b, which is the first digit in an instruction machine language code.

02:24 So b here is the 11th number in 4 -bit hexadec decimal representation.

02:33 So this is exactly as we are presenting the number 11, because a is equivalent to 10, while b is the 11th in this order...

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