Question
Antimony (Sb) has two naturally occurring isotopes: Sb-121 and Sb-123. If Sb-121 has a 57.21 $\%$ abundance and a mass of $120.9 \mathrm{amu},$ and $\mathrm{Sb}-123$ has a $42.79 \%$ abundance and a mass of 122.9 amu, calculate the atomic mass for antimony using the weighted average mass method.
Step 1
For Sb-121, the decimal abundance is $0.5721$ (obtained by dividing $57.21 \%$ by $100$). Similarly, for Sb-123, the decimal abundance is $0.4279$ (obtained by dividing $42.79 \%$ by $100$). Show more…
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Antimony (Sb ) has two naturally occurring isotopes: Sb -121, which has a percent abundance of 57.21 % and a mass of 120.90 amu , and Sb -123, which has a 42.79 % abundance and a mass of 122.90 amu . Part A Calculate the atomic mass for antimony using the weighted-average mass method.
Antimony (Sb) has two naturally occurring isotopes: Sb-121 that has a percent abundance of $57.21 \%$ and a mass of $120.90 \mathrm{amu}$, and $\mathrm{Sb}-123$ that has a percent abundance of $42.79 \%$ and a mass of $122.90$ amu. Calculate the atomic mass for antimony using the weighted average mass method. (4.5)
Atoms
Trends in Periodic Properties
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