00:01
In this problem, we are given some of the species where the central atom has a tetrahedral arrangement.
00:10
We have to identify the species which are optically active.
00:15
First of all, we'll see what is an optically active substance.
00:19
Optical active compound is that compound which has a chiral center.
00:27
And chiral center means the atom which is bonded.
00:36
To four different substituents.
00:48
So in all these given species, we will see if the central atom is bonded to all the four different substituents, that will be considered optically active because of the presence of carol center.
00:59
Otherwise, the compound will be optically inactive.
01:02
So let's start with the first compound.
01:03
The first one is ch, c, h, c, lbrf.
01:08
If we draw the structure, we can have an arrangement where carbon is a central atom and it is bonded to hydrogen, chlorine, bromine, and fluorine.
01:22
And we can see central atom carbon is bonded to four different substituents.
01:29
So this compound is optically active.
01:39
Then we have the second compound where we have nbr, cl2h, and overall it has a positive charge, which is on the central atom.
01:49
Central atom here will be nitrogen.
01:51
And if we write the structure, we can write nitrogen, bonded to hydrogen this side, then wanted to chlorine this side, bromine, and bonded to chlorine this side also.
02:03
And there is a positive charge on nitrogen...