0:00
Hello.
00:01
So here, part a, we have that the research hypothesis here is that mu is going to be equal to 600 ,000 viewers per day.
00:10
So the research hypothesis should already be stated as the alternative hypothesis.
00:14
So here we have that h -not is going to be mu is equal to 600.
00:18
This is in thousands.
00:19
The mu is equal to 600.
00:20
And then the alternative hypothesis is going to be that mu is not equal to 600.
00:25
So then for part b, we have the size of our sample is n is equal to 40 and a degrees of freedom is one less of 39 the mean viewing audience x bar is 612 ,000 daily viewers and the standard deviation is 65 ,000 viewers so therefore our test statistic then is going to be equal to x bar minus mu not that's 612 minus 600 and then divided by s divided by the square root of n so divided by 65 divided by the square root of 40, which is going to give us 1 .17.
01:03
So then from this, we get that the area in the upper tail row of our table here gives us that the area in the tail to the right of t equals 1 .17 is between 0 .20 and 0 .10.
01:21
So if we double these amounts, the p value then must be between 0 .40 and 0 .2...