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APPLICATIONSArt History. Leonardo da Vinci's drawing relating a human figure to a square and a circle is shown. Find an expression for the following:A. The area of the squareif the man's height is $5 x$ feetB. The area of the circleif the waist-to-feet distance is $3 a$ feet.Leave $\pi$ in youranswer.(PICTURE NOT COPY)

a. $25 x^{2} \mathrm{ft}^{2}$b. $9 a^{2} \pi \mathrm{ft}^{2}$

Algebra

Chapter 5

Exponents and Polynomials

Section 1

Rules for Exponents

Polynomials

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Lectures

01:32

In mathematics, the absolu…

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00:40

ART HISTORY Leonardo da Vi…

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Given the circle below wit…

00:45

In the figure, $\overline{…

02:18

Geometry A semicircle of r…

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A figure displaying some o…

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Find the indicated measure…

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$\overline{A B}$ is the di…

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The area of a circle with…

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approximate the (a) circum…

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so are drawing relating off human figure to Esquire. The circle is shown in subdivision here. We need to find the aerial to spoil If the man's height iss five X pete So let us condo consider yes, they will do firing speed. You know the area off the spoiler is given by a will to guess square so that this substitute yes is equal to five x Forget fine excess square. We know that the product will for exponents states that if a product ex wife is raised to poverty and then it can be bitterness Expo Pavilion multiplied by white over here. So let us raise each factor off the product to over. Do we get by square? And it's this way going simplifying this. We get 25 excess point. Since this is the idea, the unit will be 25 extra square feet square. So the idea off the squares next solution be We need to find the area off the circle. If the veins to two feet distance this three feet. So let us. He obviously went to a three year feet. We know that the area of the circle is given by the formula equals two pi r squared So substitute the value of our here. So we get by the the was quite so Let us use the power of product rule for the exponents. So we get Bye in tow the Squire into a square. So on simplifying this we get nine bye eastward. Hence the area of the circle is a equals 29 by Esquire squib.

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