00:01
So we know that they tell us that the, we have a probability of 0 .737 of a flight being on time.
00:09
And in june of 2008, they said that there were 10 ,288 flights into boston during june of 2008.
00:23
That's a lot of flights.
00:25
And we want to estimate a couple of questions.
00:27
But before we do, we know that this distribution of end.
00:31
Times p and n times 1 minus p are both going to be greater than a equal to 5.
00:36
So this distribution is approximately normal for the number of planes arriving on time.
00:42
We have a very large sample size, ours with a very large n.
00:45
And we know that the mean is going to be 0 .737 is going to be n times p, which is 0 .737 times that 10 ,288.
00:56
10 ,288.
00:59
Again, that's a comma.
01:02
And that comes out to be 7 ,582 .256.
01:08
And i'm actually going to store that value in my calculator is like alpha a.
01:12
That way i don't have to keep typing it in when i convert to z values.
01:15
And now we want to find the standard deviation, which is a square root of n times p.
01:20
So this value times 1 minus p, and then we'll have to make sure that that's square rooted.
01:24
And so we take that value times, this value, times 1 minus .737.
01:34
I get that answer and take it to the .5 or square root it.
01:38
And i find the standard deviation is 44 .6.
01:42
We'll say 5 ,6.
01:44
And i could actually take that value and store it in my calculator.
01:47
I happen to have this one stored as a and i have this one stored as x.
01:53
But you could store it as whatever you want, whichever variability you want, whatever is convenient for you...