00:01
This question relates to the reaction between sodium phosphate and cobalt 2 nitrate.
00:11
First, to answer question a, we need to write the balanced equation for this reaction.
00:20
So we have sodium 3 phosphate reactant with cobalt 2 nitrate.
00:31
This reaction produces a precipitate.
00:36
So these two reactants are dissolved in water.
00:39
They are in equal solution.
00:42
And the reaction between them two produces a precipitate of cobalt to phosphate, which is purple, and sodium nitrate, which remains in solution.
01:05
Okay? equals.
01:07
So we need to balance this react this equation.
01:12
We have three sodium, only one, we place a three.
01:16
Then we verify nitrate, we have three nitrate, but two here.
01:21
So we need to exchange the coefficients.
01:28
We need to place a three here.
01:32
Now we have six, and then we need to have then a six here.
01:40
By having a six in front of sodium nitrate, we unbalanced sodium, so we need to place a two here.
01:51
Now we verify the phosphate to phosphate, two phosphate, two phosphate.
01:55
So this is the balanced reaction.
01:58
In question b, we need to determine which of these two reactants is the limiting reactant or the reactant in excess based on information provided on four experiments or trial in the first experiment you mix 5m .l of sodium phosphate with 10m.
02:21
Of cobalt 2 nitrate...