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Apply the loop rule to loop akledcba in Figure 21.55.

see solution.

Physics 102 Electricity and Magnetism

Chapter 21

Circuits, Bioelectricity, and DC Instruments

Direct-Current Circuits

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Washington

Lectures

11:31

In electrical engineering,…

12:44

03:40

Apply the loop rule to loo…

02:24

03:12

01:48

02:06

01:42

02:23

02:41

Apply the loop rule to Loo…

04:33

02:05

Apply the junction rule at…

00:49

01:25

Figure 22.66What are t…

02:14

Determine the magnetic fie…

00:34

Make a conjecture about th…

00:18

00:27

00:14

01:13

Copy each figure and find …

01:04

Hi. The given problem here this is Ah, complicated circuitry Ground having to closed loops The upper loop its name pressed a B B E l E a. And the lower closed loop will be named as a k a l e f g h i g a No In this junction at this junction, eight current I three is entering, which is getting divided into two parts. I won and I do so using junction rule at Junction A become to know that this I three is equal to I one class. I do. No this current I one will you be in same through this sell off. Even we passed through this branch. The current will wins him as Ivan. Then we'll pass through this resistance r five. Then we'll come here at the Junction E and this current I to passing through this arm a l it will join with Ivan again at this is current title will join with Ivan again a junction e and we become I treat which will pass through this ranch F g h I, and will enter into the cell into the negative terminal of self in three again and will come out from its positive terminal as the same current I three. So this is the current distribution in this circuit. Now, in this given problem, we have tow obtain an equation for the closed loop. Mm. He l e b c b A this upper room, which is a k n e b, C b and again A. Here we apply jobs Loop rule, which says the currents which are flowing in the closed loop in clockwise direction, will give a positive potential drop. So as Ivan is passing from C to D means in a clockwise direction. So the potential drop here will be positive potential Drop here will be positive potential drop here for Ivan Do toe Ivan across this firearm will also be positive. But as I do is passing here through this are two internal instance and through this capital are too. So the potential rob here will be counterclockwise so will be taken as negative. Similarly e m f even will be sending its current in clockwise direction like this, so even will be taken as positive and it too will send its current in the same clothes group in counterclockwise direction. So the CMF will be taken as negative hence applying this rule. Algebraic sum off potential drops. You have this algebraic son off potential drops. All the potential drops taking place in the loop should be equal toe. Algeria breaks off all the M s in that loo job. Reckson means some with proper sign. Convention. Positive or negative? Hence we can say for the potential drops. This becomes, I run into organ. Possibly. Then again positive. I won, but small are one then I two are too negative. Similarly capital are too. This is also negative. And for our five disease positive again Ivan are five is going toe even is positive. But it too is negative. Yeah, So it becomes the equation for the given loop and the answer for the given problem. Thank you.

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Apply the loop rule to loop abcdefghija in Figure 21.55.

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