00:01
The russian soyuz module is preparing to dock with the international space station.
00:06
We want to find the average gravitational force of attraction between the two spacecraft when the soyuz is docked and when it is 110 meters away from the space station.
00:17
Here i've drawn a diagram of both positions.
00:21
Position 1 is when the soyuz is docked to the iss and position 2 is when it is 110 meters.
00:30
Away from the iss.
00:33
So to find the average gravitational force of attraction, here i will notate the average as f big g with a line above it to indicate average.
00:48
This is equal to the integral of from r2 to r1 or r1 to r2 times the gravitational force, with respect to distance.
01:06
And since we integrated over distance, to find the average, we just take the result of the integral and divided by the difference between the distances, which is r2 minus r1.
01:26
So here if we rewrite this, or if we fill in fg, we get g, m, soyuz, m, i, iss divided by r squared dr.
01:45
If you plug this into a calculator, you'll find that the average force is 2 .01 times 10 to the negative 4 newton's.
01:57
This is the average force that the soyuz module will experience as it docks to the iss...