Question
Approximate the value of each of the given integrals by use of the trapezoidal nule, using the given value of $n$.$$\int_{2}^{6} \frac{d x}{x+3}, n=4$$
Step 1
This is given by the formula $\Delta x = \frac{b-a}{n}$, where $a$ and $b$ are the limits of the integral and $n$ is the number of subintervals. In this case, $a = 2$, $b = 6$, and $n = 4$. So, $\Delta x = \frac{6-2}{4} = 1$. Show more…
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