00:01
For this question we're looking at the decay of sodium 22 via electron capturing.
00:10
So electron capturing involves a beta minus particle.
00:15
And the final product often would get a neutrino since we have a beta minus particle involved, plus an unknown nucleate from this reaction.
00:30
And to figure out what is the unknown nucleate, we look at the conservation of the proton number, and the nucleon number.
00:40
So it's total of 22 nucleons for left -hand side, right -hand side.
00:45
The proton number is 10, right? and we can figure out from the proton number that the element must be neon.
00:54
All right, so now that we have this equation, we can now start to figure out what is the energy that was imparted to the neutrino.
01:04
From this reaction, you can figure out what is the energy? that was released and we assume that the energy release, right, so there's an assumption that the energy released in this reaction is all imparted the antideotrino, right? because the neon has much, much greater mass than the antediturino.
01:37
We expect this to be like zero, right? we assume it's zero.
01:41
So most of the kinetic energy, we assume to be imparted to your neutrino.
01:48
Alright, so now to find what is this energy that was released, we need to take the mass defect or like the change in the mass from the reactors to the products, multiplied by c squared...