00:01
In this question, we need to find the fifth order teta polynomial center at different points.
00:09
So let's first take the derivative for f at the beginning.
00:16
And we need to take the derivative up to fifth order.
00:20
Since it's a basic function, so it's not that difficult to do.
00:35
Okay, so this is, these are the derivatives of f.
00:41
Up to fifth order.
00:47
Now if we consider the center to be 0, so if 0 equals to 0, the first of the derivative, as 0 equals to 1, the second of the directive equals to 0, third order directive equals to minus 1, fourth of the derivative equals 0, and the last piece is 1.
01:13
And if we choose the center to be, pi the first of the derivative equals 0 this so the original function equals 0 the 1 the 1 second derivative 0 3rd order derivative 1 4th order derivative 0 5th order derivative 0 5th order derivative equals to minus 1 so according to this by the notation we denotes the taylor polynomial center that equals 0 by p5 which is so we only have three terms survived so the linear term x minus the cubic term 1 over 6 x cubed and the fifth of the term plus 1 over 120 x3 5 so all of this coefficient comes from the factorials and we denote the taylor polynomial centered pi by q5 again, only three terms survive, the linear term, cubic term.
02:30
The center should be pi.
02:33
So we have minus x minus pi.
02:37
And then we have a cubic term.
02:43
We have a fifth order term.
02:50
So these two are p5 and the q5.
02:52
We need to figure out.
02:56
Once we have this, we can graph if the original function and these two tailor polynomials on the same coordinate system.
03:07
So it looks like this.
03:10
Let's label some points...