00:05
Let's determine if different substituents could be orthopara or meta -directors.
00:13
And let's try the first one.
00:15
Well, we have an alkene and a nitral group.
00:19
We know that an alkyne is like a lot of alkyl groups, it will be orthopar directing.
00:25
However, nitral groups are very, very strong metadirecting groups.
00:33
In fact, if this was a substituent on a benzene ring, it will try to go for resonance towards the nitrogen, which would make it metadirecting.
00:53
No2 is going to be our strongest deactivating group.
01:00
And if it's a very strong deactivating group, what does that say about its director? or what does that say about what it directs? it would be metadirecting.
01:20
What about methanol? if this was bonded to a benzene rube, ring.
01:30
Well, methanol would function a lot like just regular alcohol.
01:34
In fact, if this was connected to a benzene, it would probably be like a methoxy, which is an ether, which functions a lot like alcohols or a lot like a phenol in terms of directing and activating.
01:54
It is an activator.
01:56
So that should tell us that it is orthopera, because these loan, these loan pairs on the oxygen would be involved in resonance and would donate those electrons to the benzene ring.
02:17
What about carboxylic acid? if we had a carboxylic acid bonded to a benzene ring, well, we know that there's a double bond.
02:37
And whenever there's a double bond or a triple bond, it would like to take those electrons, and it will pull those electrons through induction and resonance.
02:50
In fact, this would be a meta -directing group...