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Area A garden is rectangular with a width of 8 fe…

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Problem 23 Easy Difficulty

Area A swimming pool is 20 feet wide and 40 feet long. If it is surrounded by square tiles, each of which is 1 foot by 1 foot, how many tiles are there surrounding the pool?

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Prealgebra

Chapter 1

Whole Numbers

Section 8

Area and Volume

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Video Transcript

are you the graph to show how to solve this question, when knows that the rectangular swimming poor is 30 ft by 40 ft. That is the error of the blue region. We know that there is a rectangular scrape of grass of uniform whites that is around the swimming pool. And the area of this grip is 624 sq ft. That is the area of a grain region. And that big rectangular, so it's white. Yes. 30 plus two X. And it's nancy is 40 plus two X. And the area of the grass is just the difference of the bigger rectangle and the smaller right tangle enhance. The area of the bigger right angle is 30 plus two eggs times 40 plus two X. And the area of the small rectangle, which is the area of the swimming pool. Yes, 38 times 40. And their difference is the area of the grass, which is 624. We can simplify this equation as four eggs Squared plus 140 acts. You calls 624. We subtract 624 from both sides And then divide both sides by four. Then we got a craving ax squared Last 35 eggs, Miners. A 156 Ego zero. So we can identify the coefficients of the constructive equation as A cause one because 35. And see calls miners a hand bird and 56. Then we can use the formula. No, you just substitute A. B and C. With their values into this form. And this echoes -35 plus. um miners For three or 2. Hence The two Solutions of the Quadratic Equations. Xy ankles, miners 39 add two equals four. But the next cannot be negative. So we just eliminated the first solution and has the whites of this crap. Yes for

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Problem

Area A garden is rectangular with a width of 8 fe…

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Charles P. McKeague

Prealgebra

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Prealgebra

Charles P. McKeaguePrealgebra

Charles P. McKeague

Prealgebra