Question
Area bounded by $y=f^{-1}(x)$ and tangent and normal drawn to it at the points with abscissae $\pi$ and $2 \pi$, where $f(x)=\sin x-x$ is(ii) $\frac{\pi^{2}}{2}-1$(b) $\frac{\pi^{2}}{2}-2$(c) $\frac{\pi^{2}}{2}-4$(d) $\frac{\pi^{2}}{2}$
Step 1
Using the chain rule, we get $f'(x) = \cos x - 1$. Show more…
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