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Problem 38 Easy Difficulty

Area of a Rectangle A rectangle has an area of 39 square feet. If the length is 13 feet, what is the width?


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Prealgebra

Chapter 1

Whole Numbers

Section 8

Area and Volume

Related Topics

Decimals

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Watch More Solved Questions in Chapter 1

Problem 1
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Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38

Video Transcript

Okay, So our length is our wit. Plus there can. Yours are with w, and then a perimeter is 82 yards. So we need to fund what are length and with or so it's dimensions. Now, I want to go ahead with Apply at both of these by two because you know, you got your length plus dealing explicitly with coast with or two times l and then two times w So this isn't Give me to W plus 26 then to w so I'm gonna add these together t equal into this is going to before it over u equals 20 for over U plus 26 minus 80 equals 82. So we're gonna subtract 26 from both sides, and this is going to give us Ford over u equals 56. And then we're gonna divide out four, which gives us 14. So w is equal to 14. So our wit is equal to 14 Now, our length we have to pull in here, so 14 plus 13 is 27. So I'm gonna such a to l for the now we're gonna multiply 27 butts who, plus 14 but two So This is 28 27 times two is 54 54 plus 28 is indeed 82.

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Charles P. McKeague

Prealgebra

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