Question
Area of a triangle in the plane:$$A=\pm \frac{1}{2}\left(x_{1} y_{2}-x_{2} y_{1}+x_{2} y_{3}-x_{3} y_{2}+x_{3} y_{1}-x_{1} y_{3}\right)$$Find the area of a triangle whose vertices are$(6,-2),(-5,4),$ and (-1,7).
Step 1
We have $(x_{1}, y_{1}) = (6, -2)$, $(x_{2}, y_{2}) = (-5, 4)$, and $(x_{3}, y_{3}) = (-1, 7)$. Show more…
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