00:01
In the given problem here, this is a uniform magnetic field which is perpendicular to the plane of paper and coming out of it.
00:17
In this magnetic field there is a circuit, a rectangular circuit which is having a resistance r, having the value of 12.
00:38
0 .5 om.
00:41
It is moving towards right with the velocity v having a magnitude of 3 .0 meter per second means it is being entered into this magnetic field.
00:59
L length of this circuit here is given as l is equal to 75 .0 centimeter or we can say this 0 .75 meter and here its width is b is equal to 50 .0 centimeter or we can say this is 0 .5 meter.
01:34
The magnetic field, magnitude of this magnetic field, which is coming out perpendicularly to the plane of paper, is given as b is equal to 1 .25 tesla.
01:47
Now, in the first part of the problem, we have to find the current induced in this circuit when it is being entered into the magnetic field.
02:02
So when the circuit is entering into the magnetic field, its right arm having this length l will be intercepting the magnetic field.
02:32
So, motional emf induced across the ends of this length will be epsilon is equal to b into v into l.
02:50
Hence, current induced in this circuit will be given by oms law as emf induced means epsilon divided by r.
03:02
Or we can say this is bvl by r.
03:07
Plugging in all known values for b, this is 1 .25 tesla multiplied by speed, which is 3 .0 meter per second multiplied by length, which is 0 .75 meter.
03:23
And divided by resistance of this circuit, which is 12 .5 oom.
03:29
So in numerator we get 2 .625 volt, the emf induced.
03:41
Denominator is 12 .5 om.
03:45
So finally, the magnitude of this current comes out to be 0 .21 ampere.
03:55
Using fleming's right hand rule, the direction of this current induced in the right arm of the circuit is downward.
04:34
So in the circuit it will become clockwise...