Question
Argument of solutions of the equation $\mathrm{z}^{2}+\mathrm{z}|\mathrm{z}|+\left|\mathrm{z}^{2}\right|=0$ is(a) $\frac{\pi}{3}$(b) $\frac{2 \pi}{3}$(c) $\frac{4 \pi}{3}$(d) Both(b) and (c)
Step 1
We can write $z$ in polar form as $z = r(\cos \theta + i \sin \theta)$ where $r$ is the modulus of $z$ and $\theta$ is the argument of $z$. Show more…
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