Question
Aromatic compounds such as benzene react with alkyl chlorides in the presence of $\mathrm{AlCl}_3$ catalyst to yield alkylbenzenes. This reaction occurs through a carbocation intermediate, formed by reaction of the alkyl chloride with $\mathrm{AlCl}_3\left(\mathrm{R}-\mathrm{Cl}+\mathrm{AlCl}_3 \longrightarrow \mathrm{R}^{+}+\mathrm{AlCl}_4{ }^{-}\right)$. How can you explain the observation that reaction of benzene with 1-chloropropane yields isopropylbenzene as the major product?
Step 1
The reaction starts with the formation of a carbocation intermediate. In this case, 1-chloropropane reacts with $\mathrm{AlCl}_3$ to form a carbocation intermediate, which is a secondary carbocation ($\mathrm{R}^{+}$). Show more…
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Aromatic compounds such as benzene react with alkyl chlorides in the presence of $\mathrm{AlCl}_{3}$ catalyst to yield alkylbenzenes. This reaction occurs through a carbocation intermediate, formed by reaction of the alkyl chloride with $\mathrm{AlCl}_{3}\left(\mathrm{R}-\mathrm{Cl}+\mathrm{AlCl}_{3} \rightarrow \mathrm{R}^{+}+\mathrm{AlCl}_{4}^{-}\right) .$ How can you explain the observation that reaction of benzene with 1 -chloropropane yields isopropylbenzene as the major product?
Aromatic compounds such as benzene react with alkyl chlorides in the presence of AlCla catalyst to yield alkylbenzenes. The reaction occurs through a carbocation intermediate, formed by reaction of the alkyl chloride with $\mathrm{AlCl}_{3}(\mathrm{R}-\mathrm{Cl}+$
Attempted alkylation of benzene with 1 -chlorobutane in the presence of $\mathrm{AlCl}_{3}$ gave not only the expected butylbenzene, but also, as a major product, (1-methylpropyl)benzene. Write a mechanism for this reaction.
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