Question
Arrange from least to most in moles: $3.00 \times 10^{24}$ atomsNe, 4.25 mole $\mathrm{Ar}, 2.69 \times 10^{24}$ atoms $\mathrm{Xe}, 65.96 \mathrm{g} \mathrm{Kr}$ .
Step 1
For the atoms of Ne and Xe, we use Avogadro's number ($6.022 \times 10^{23}$ atoms/mole). For the mass of Kr, we use its molar mass (83.798 g/mole). Show more…
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Arrange from least to most in moles: $3.00 \times 10^{24}$ atoms Ne, 4.25 mole $\mathrm{Ar}, 2.69 \times 10^{24}$ atoms $\mathrm{Xe}, 65.96 \mathrm{g} \mathrm{Kr}$ .
Arrange these quantities from smallest to largest in terms of mass: 1.0 mol of $\mathrm{Ar}, 3.0 \times 10^{24}$ atoms of Ne, and 20 $\mathrm{g}$ of $\mathrm{Kr}$ .
Put the following elements in order from smallest to largest mass: (a) $3.79 \times 10^{24}$ atoms Fe (b) $19.921 \mathrm{mol} \mathrm{H}_{2}$ (c) 8.576 mol $\mathrm{C}$ (d) 7.4 mol $\mathrm{Si}$ (e) 9.221 mol $\mathrm{Na}$ (f) $4.07 \times 10^{24}$ atoms $\mathrm{Al}$ (g) 9.2 mol $\mathrm{Cl}_{2}$
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