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Chapter 3, problem 68, says, arranged the atoms according to the decreasing effective nuclear charge experienced by their valence electrons.
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The atoms we have are sulfur, magnesium, aluminum, and silicon.
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The atomic numbers for these are 16, 12, 13, and 14, respectively.
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So to demonstrate this, let's use an atom.
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So we're going to have, we're going to do the smallest one, which would be magnesium.
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So we'll have 12 protons in the nucleus.
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The first energy level, we'll have two electrons.
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The second energy level, we'll have eight.
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The third energy level for magnesium and a neutral atom will have two.
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And this will give us a total of 12.
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We have two, four, six, eight, ten, and twelve.
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So this is magnesium.
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The equation for effective nuclear charge is your z effective is equal to the charge of the nucleus minus the charge of the shielding electrons.
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So the charge of our nucleus here for magnesium is 12, and we're going to subtract the number of shielding electrons, which would be 10.
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This is the outer electrons.
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On the outer energy level, the ones that are inside are the core electrons are shielding.
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So that minus 10 would give us two...