00:02
So oxygen has 1 s2, 2s2, 2b4, so 4 electrons.
00:12
And all the subsequent versions are bonded versions of this oxygen atom will be stable than the oxygen atom itself because bonding stabilizes a structure.
00:31
The number of balance electrons in this case is 12.
00:34
Here you lose an electron, so you have 11, and here you gain an electron, so you have 13.
00:42
So let's write out the electronic configurations for this.
00:47
This is star, sigma, and pz, 2, pi, npx equals to pi npx, equals to pi npi, 2, and 2, and then pi star npx equals to pi star npy, 1 and 1.
01:04
The bond order in this case, if you subtract the number of bonding from the anti -bonding and then divide by 2 will be 2.
01:14
Let's fill out the electronic configuration in this case.
01:18
Star 2, sigma, np z to pi npx equals to pi mp .y is 2 and 2, and then pi star npx equals to pi star npy.
01:35
Is zero...